x^2-9x+64-8600=0

Solution for x^2-9x+64-8600=0 equation:

x^2-9x+64-8600=0

We add all the numbers together, and all the variables

x^2-9x-8536=0

a = 1; b = -9; c = -8536;
Δ = b2-4ac
Δ = -92-4·1·(-8536)
Δ = 34225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{34225}=185$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-185}{2*1}=\frac{-176}{2}
=-88
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+185}{2*1}=\frac{194}{2}
=97
$